Sunday 15 November 2015

Lab Report : Practical 3 Phase Diagram Part B

TITLE
Phase Diagrams Part B

OBJECTIVES
To determine the mutual solubility curve for phenol and water and to apply phase rule in explaining the liquid-liquid system that is partially miscible with each other.

DATE OF EXPERIMENT
3 November 2015

INTRODUCTION      
Miscibility is the capability of substances to mix in any proportions, forming a homogeneous solution without separation of two phases. The liquids are said to be miscible with each other if they are capable to mix to form a homogeneous solution. It is a qualitative rather than quantitative observation—miscible, partially miscible or not miscible. (To state exactly how miscible two liquids were, a scientist would use the larger concept of solubility, usually in a specific weight or volume per liter of solution.) Two completely miscible liquids will form a homogeneous (uniform) solution in any amount. Water and ethyl alcohol, for example, are completely miscible whether the solution is 1% water and 99% ethyl alcohol, 50% of both, or 1% ethyl alcohol and 99% water.

A few liquids are miscible with each other in all proportions, for example: ethanol and water. Others have miscibility in limited proportions in other liquids, for example: etherwater, phenol-water. (Here, phenol is not really liquid, but is considered to be so since the addition of the first part of water reduces the solid's melting point under room temperature to produce a liquid-liquid system).


Phenol, also known as carbolic acid, is an aromatic organic compound with the molecular formula C6H5OH. It is a white crystalline solid that is volatile. The molecule consists of a phenyl group (−C6H5) bonded to a hydroxyl group (−OH). Phenol is used primarily in the production of phenolic resins and in the manufacture of nylon and other synthetic fibres. It is also used in slimicides (chemicals that kill bacteria and fungi in slimes), as a disinfectant and antiseptic and in medicinal preparations.

Generally, both liquids become more soluble with rising temperature until the critical solution temperature or consolute point is attained, and above this point the liquids become completely miscible. There is a big possibility that any pair of liquids can form a closed system, whereby both upper and lower critical solution temperatures exist, however it is not easy to determine both the temperatures (before the substance freezes or evaporates) except for nicotine and water.

At any temperature below the critical solution temperature, the composition for two layers of liquids in equilibrium state is constant and does not depend on the relative amount of these two phases. The mutual solubility for a pair of partially miscible liquids in general is extremely influenced by the presence of a third component.

LIST OF APPARATUS




water bath



thermometer


test tubes


test tube rack


measuring cylinder


aluminium foil


LIST OF CHEMICALS



phenol


distilled water


EXPERIMENTAL PROCEDURES

1. Five tightly sealed test tubes containing phenol with concentrations scale between 8% to
    80% were prepared using different proportions of phenol and distilled water.


2. To increase the temperature, the tightly sealed test tubes were heated in the water bath
    while being stirred and shaken.
3. The temperature for each of the test tubes at which the turbid liquid becomes clear were
    observed and recorded.


4. The test tubes were removed from the hot water bath and they were allowed to cool to
     the temperature at which the liquid in the test tubes become turbid and two layers were
     separated. The temperature were recorded.


5.  The average temperature for each test tubes at which two phases were no longer seen or at
     which two phases exist were determined. Part of the test tubes were cooled besides being
      heated.
6. A graph of temperature at complete miscibility against phenol concentrations was drawn. The critical solution temperature was determined.

RESULTS

Test tube
Concentration of phenol (%)
Volume of phenol (mL)
Volume of distilled water
(mL)
Temperature (˚C)
When homologous solution is formed during heating
When two phases are seen during cooling
Average
A
8
1.0
11.5
40
37
38.5
B
20
2.5
10.0
49
43
46.0
C
40
5.0
7.5
62
55
58.5
D
60
7.5
5.0
56
50
53.0
E
80
10.0
2.5
40
35
37.5


QUESTIONS
1. Plot the graph of temperature at complete miscibility against phenol concentrations.
    Determine the critical solution temperature.



Critical solution temperature is the maximum temperature at which two-phase region exist. Based on the result of the experiment and the graph drawn, the critical solution temperature is 62 ˚C.

2.  Discuss the diagrams with reference to the phase rule.
     The phase rule is a useful device for relating the effect of the least number of independent
     variables (temperature, pressure and concentration) upon the various phases (solid, liquid  and gas) that can exist in an equilibrium system containing a given number of components.
     The diagram drawn shows the mutual solubility curve for a two components condensed
     system having one phase only, which is liquid phase. The components are phenol and
     distilled water. Since phenol and distilled water are partially miscible with each other, they
     are only miscible at particular conditions. The conditions can be figured out by using the
     phase rule, which is F = C - P + 2. F is the number of degree of freedom, C is the number
     of components in the system while P is the number of phases present in the system. The
     system used in this experiment is phenol-water system. So, C = 2, P = 1 (liquid phase
     for both phenol and water based on mutual solubility curve drawn) and F = 2 - 1 + 2 = 3.
     However, since the experiment is conducted at pressure of 1 atm, the pressure is fixed and
     the degree of freedom should be reduced by one. Therefore, only temperature and
     concentration are needed in order for us to define completely the system. We can easily
     find out the concentration of phenol used from the graph if the temperature used is
     provided.

 3.  Explain the effect of adding foreign substances and show the importance of this
     effect in pharmacy.
     When a foreign substance is added to phenol-water system (binary system), the binary
     system becomes ternary system since the system now contains three components. Two
     conditions may occur depending on the solubility of the foreign substance in two of the components. If the foreign substance is soluble only in one of the components, the mutual solubility of the two liquid components is decreased. If the original binary mixture has an upper critical solution temperature, it is increased by addition of the foreign substance as the third component. If the original binary mixture has a lower consolute temperature, it is lowered by the addition of foreign substance s third component. For instance, if naphthalene is added to a mixture of phenol and water, it dissolves only in the phenol and thus, raising the consolute temperature. If potassium chloride is added to the phenol-water system, it dissolves only in the water and thus, raising the consolute temperature. If the foreign substance is soluble in both of the liquids, the mutual solubility of the liquid pair is increased. This occurrence is known as blending. The upper critical solution temperature will be lowered and the lower critical solution temperature will be increased. An example for this is the addition of succinic acid or sodium oleate. This effect is important in pharmacy as it enables the production of highly concentrated tar acids solutions to be used as disinfectants. However, this effect causes the formation of insoluble complexes during preparation of drugs, leading to the inefficiency of biological availability of drugs. Furthermore, this effect enables the selection of the best solvent for a drug or for a mixture of drugs, thus overcoming problems that arise during preparation of pharmaceutical solutions. 

DISCUSSION
          To analyze the phase diagrams, phase rule is always used. The phase rule is a useful device for relating the effect of the least number of independent variables (for example: temperature, pressure and concentration) upon the various phases (solid, liquid and gaseous) that can exist in an equilibrium system containing a given number of components. The phase rule is expressed as F = C - P + 2 in which F is the number of degrees of freedom in the system, C is the number of components in the system and P is the number of phases present in the system.

          Phase is defined as a homogenous, physically distinct portion of a system that is separated from other portions of the system by bounding surfaces. The number of components is the smallest number of constituents by which the composition of each phase in the system at equilibrium can be expressed in the form of a chemical formula or equation. The number of degrees of freedom is the least number of intensive variables (temperature, pressure, concentration, refractive index, density and viscosity) that must be fixed to describe the system completely. By using the phase rule, the degree of freedom for a two component system having one liquid phase is F = 3. However, during this experiment, since the variable pressure is fixed, F is reduced to 2, which means that we need to know the temperature and concentration to define completely the system. The degree of freedom for a two component system having two liquid phase is F = 2. However, F is reduced to 1 as pressure is fixed. In this case, only temperature need to be known to completely define the system.


         The diagram above shows the mutual solubility curve for phenol-water system. Phenol and water are partially miscible with each other. The curve shows the limits of the temperature and concentration within which two liquid phases exist in equilibrium.  The region outside this curve contains systems having only one liquid phase. Starting at point a, equivalent to a system containing 100% water at 50 ˚C, the addition of known increments of phenol to a fixed weight of water at 50 ˚C, will result in the formation of a single liquid phase until the point b is reached, at which a minute amount of  a second phase appears. The concentration of phenol and water at which this occurs is 11% by weight of phenol in water. Analysis of the second phase, which separates out on the bottom, shows it to contain 63% by weight of phenol in water. This phenol-rich phase is denoted by the point c on the phase diagram. Once the total concentration of phenol exceeds 63% at 50 ˚C, a single phenol-rich liquid phase is formed. The maximum temperature at which the two-phase region exists is termed the critical solution or upper consolute temperature. In the case of the phenol-water system, the critical solution temperature is 66.8 ˚C. All combinations of phenol and water above this temperature are completely miscible and yield one-phase liquid system.

           However, using the result of the experiment, the critical solution temperature obtained is 62 ˚C. This is because several errors have occurred during the experiment and therefore, several precautions have to be taken. First, we have to seal the test tubes thoroughly using aluminium foil immediately after we add phenol into the test tubes containing distilled water as phenol is very volatile. Any delay in doing so will result in the evaporation of phenol, causing the concentration of phenol used to be inaccurate. Besides, we have to carry out the experiment in the fume cupboard. This is because phenol is both volatile and carcinogenic. Furthermore, we have to measure and record the temperature at which two phases are separated and two phases are no longer seen accurately. The temperature have to be taken immediately once the two phases show observable changes. In addition, parallax error should also be avoided by ensuring that the observer's eye is perpendicularly in line with the scale reading of the thermometer while taking the readings. It has to be known that the  convex meniscus of mercury is totally different with the concave meniscus of water. In order to increase the accuracy of the result of the experiment, the experiment should be repeated more times for each set of readings and the average readings are then calculated.


CONCLUSION
The objective of the experiment is achieved. The mutual solubility curve for phenol and water is determined. Based on the mutual solubility curve, the critical solution temperature obtained is 62 ˚C. Temperature is a factor that can influence the mutual solubility of phenol and water. Since phenol and water are partially miscible with each other, they will only produce a single liquid phase system at a particular temperature and concentration provided the pressure is fixed.


REFERENCES
            Florence, A.T. & Attwood, D. 2006. Physicochemical Principles of Pharmacy. 4th Edition.                            London: Pharmaceutical Press.


Sinko, Patrick J, Martin’s Physical Pharmacy and Pharmaceutical Sciences 5 th editon, Lippincott Williams & Wilkins, 2005, page 51.

            Connors, K.A. & Mecozzi, S. 2010. Thermodynamics of Pharmaceutical Systems. 2nd                                Edition. New Jersey: John Wiley & Sons.








Lab Report : Practical 3 Phase Diagram Part A

PRACTICAL 3: PHASE DIAGRAM
PART A

TITLE:
Determination of Phase Diagram for Ethanol/Toluene/Water System Theory

OBJECTIVES:
1. To determine the solubility limits in a ternary system of water and two other liquids  (ethanol and toluene), where one of which is completely miscible (ethanol) and the other is partly miscible with water (toluene).
2. To apply the concept of construction of the solubility curve of the system being studied on triangular diagram.
3. To understand the concept of miscibility and phase diagram for three-component system.
4. To understand Phase Rules that relate to the use of triangular coordinates to know the mutual solubility of liquids in a two phase system.

DATE OF EXPERIMENT
3rd November 2015.

INTRODUCTION
            There are various types of products that are produced in pharmaceutical formulations. The making of pharmaceutical formulation often involve the mixing of multiple component together to achieve homogenous form. This is usually possible by knowing the exact ratio of each component to be mixed with regard of some other condition such as temperature.
             Following the basis of describing the effect of intensive variable to various phase in a system at equilibrium, which is the phase rule, it is determine that this system have 4 degrees of freedom. The four degrees of freedom are - temperature, pressure, and any two from the three component concentration. 

F = C – P + 2                          where F refers to Degrees of Freedom;
F = 3 – 1 + 2                                      C refers to Component concentration;
F = 4                                                   P refers to Phase.

             In this experiment, there are three components of concern which were Ethanol, Toluene and Water. Water is insoluble and toluene, but as it was mixed together with ethanol, all three components can achieve homogeneous solution at equilibrium if proper proportion was used. Since it is difficult to graphically represent four variables, one variable out of the four is generally considered constant. In this experiment, the pressure is considered fixed at 1 atm, and so the number of degrees of freedom becomes three. Any horizontal section of the right-angled prism represents a three-component system under fixed condition of temperature and pressure. 
            For three component systems at constant temperature and pressure, the compositions may be stated in the form of coordinates for a triangular diagram.
Figure 1: Ternary Phase Diagram

          In the diagram above, each corner of the triangular diagram represents a pure component, which is 100% A, 100% B, 100% C. Meanwhile, each side represents two-component mixtures and within the triangular diagram itself represents ternary components. Any line parallel to a side of the triangular diagram shows constant percentage value for a component, for example: DE shows 20% of A with varying amounts of B and C. So does line FG, showing all mixtures containing 50% of B. These lines intercept with each other at K, which definitely contains 20% A, 50% B as well as 30% C. Measurements can be made this way because in a triangular diagram, the sum of all distances from K which is drawn parallel to the three sides of the diagram is same and equals to the length of any one side of the triangular diagram.
          The addition of a third component to a pair of miscible liquids can change their mutual solubility. If this third component is more soluble in one of two different components the mutual solubility of the liquid pair is decreased. However, if it is soluble in both of the liquids, the mutual solubility is increased. Thus, when ethanol is added to a mixture of benzene and water, the mutual solubility of the liquid pair increased until it reached a point whereby the mixture becomes homogenous. This approach is used in the formulation of solutions. Examples of three-component systems that has been studied include castor oil/ alcohol/ water; peppermint oil/ propylene glycerol/ water ; peppermint oil/ polyethylene glycerol/ water.
               The benefits of preparing an oily substance as homogenous water in liquid are already clear. However, what will happen to a system like this when it is diluted should be known and this can be explained through the understanding of the triangular phase diagram. Figure 1 is also for the system containing components peppermint oil polysorbate 20-water. A concentration of 7.5% oil, 42.5% polysorbate 20 and 50% water (point A in diagram) can be diluted for 10 times with water giving a solution that is still clear (now containing 0.75% of oil, 4.25% polysorbate 20 and 95% water). However, when 1 ml of water is added to 10ml of clear solution B (49% oil, 50% polysorbsate 20, 1% water) the solution becomes cloudy, point B’ (44.55% oil, 45.45% polysorbate 20 and 10% water). If 1ml of water is further added, the solution becomes clear, point B’’ (40.5% oil, 41.3% polysorbate 20, 18.2% water) but If the original solution is diluted three times (16⅓% water. 16⅔% polysorbate 20, 67% water) the solution becomes cloudy.

EXPERIMENTAL METHOD
LIST OF APPARATUS








        Conical flask 250 mL 








              Pipette 20 mL











            Burette 50 mL











           Retort stand and clamp 

                  Dropper














             Thermometer


LIST OF CHEMICALS



















                            Ethanol














                     Toluene




















              Distilled water 



PROCEDURE

1) 20 mL of a mixture of ethanol and toluene with 10% ethanol was prepared by transferring 2 mL of ethanol and 18 mL toluene with a 20 mL pipette into a conical flask.
2) A 50 mL burette was filled with water
3) The mixture was immediately titrated with water until it becomes cloudy.
4) The mixture was then added with a little water by using dropper and the conical flask was shaken well.
5) The volume of water used in titration was recorded.
6) Another 20 mL of mixture of ethanol and toluene was prepared for second titration in order to obtain an average volume of water used.
7) Step 1 to 5 were repeated by using mixture of ethanol and toluene with various ethanol percentages which consists of 25%, 35%, 50%, 65%, 75%, 90%, and 95%.
8) The room temperature was measured.
9) The percentage of each component in the mixture after addition of water is calculated.
10) The points were plotted onto a triangular paper to give a triple phase diagram at the
recorded temperature.





From Left to Right: Khoo is preparing specific volume of ethanol solution; Gan is preparing specific volume of toluene solution; Chen is titrating the mixture of ethanol and toluene of certain proportion using distilled water.






       Before Titration                                           After Titration




RESULT

Initial Percentage of ethanol (%)
Volume of ethanol (mL)
Volume of Toluene (mL)
Volume of water added (mL)
Titration I
Titration II
Average
10
2
18
0.40
0.20
0.30
25
5
15
0.60
0.50
0.55
35
7
13
1.60
1.30
1.45
50
10
10
2.20
1.90
2.05
65
13
7
2.50
2.30
2.40
75
15
5
4.50
4.30
4.40
90
18
2
11.30
11.00
11.15
95
19
1
16.20
15.80
16.00

Volume (mL)
Percentage (%)
Ethanol
Toluene
Water
Total
Ethanol
Toluene
Water
Total
2.00
18.00
0.30
20.30
9.85
88.67
1.48
100
5.00
15.00
0.55
20.55
24.33
72.99
2.68
100
7.00
13.00
1.45
21.45
32.63
60.61
6.76
100
10.00
10.00
2.05
22.05
45.35
45.35
9.30
100
13.00
7.00
2.40
22.40
58.04
31.25
10.71
100
15.00
5.00
4.40
24.40
61.48
20.49
18.03
100
18.00
2.00
11.15
31.15
57.79
6.42
35.79
100
19.00
1.00
16.00
36.00
52.78
2.78
44.44
100


CALCULATIONS

10 % ethanol initial percentage:

Percentage of ethanol = 2.00/20.30×100%

                                      = 9.85 %

Percentage of toluene = 18.00/20.30×100%

                                      = 88.67 %

Percentage of water   = 1.48/20.30×100%

                                      = 1.48 %

25 % ethanol initial percentage:

Percentage of ethanol = 5.00/20.55×100%

                                       = 24.33 %

Percentage of toluene = 15.00/20.55×100%

                                      = 72.99 %

Percentage of water    = 0.55/20.55×100%

                                      = 2.68 %

35 % ethanol initial percentage:

Percentage of ethanol = 7.00/21.45×100%

                                      = 32.63 %

Percentage of toluene = 13.00/21.45×100%

                                      = 60.61 %

Percentage of water    = 1.45/21.45×100%

                                      = 6.76 %

50 % ethanol initial percentage:

Percentage of ethanol = 10.00/22.05×100%

                                       = 45.35 %

Percentage of toluene = 10.00/22.05×100%

                                      = 45.35 %

Percentage of water    = 2.05/22.05×100%

                                      = 9.30 %

65 % ethanol initial percentage:

Percentage of ethanol = 13.00/22.40×100%

                                      = 58.04 %

Percentage of toluene = 7.00/22.40×100%

                                      = 31.25 %

Percentage of water    = 2.40/22.40×100%

                                      = 10.71 %

75 % ethanol initial percentage:

Percentage of ethanol = 15.00/24.40×100%

                                      = 61.48 %

Percentage of toluene = 5.00/24.40×100%

                                      = 20.49 %

Percentage of water    = 4.40/24.40×100%

                                      = 18.03 %

90 % ethanol initial percentage:

Percentage of ethanol = 18.00/31.15×100%

                                       = 57.79 %

Percentage of toluene = 2.00/31.15×100%
  
                                       = 6.45 %

Percentage of water    = 11.15/31.15×100%
  
                                       = 35.79 %

95 % ethanol initial percentage:

Percentage of ethanol = 19.00/36.00×100%

                                       = 52.78 %

Percentage of toluene = 1.00/36.00×100%

                                       = 2.78 %

Percentage of water    = 16.00/36.00×100%

                                       = 44.44 %


Ternary Phase Diagram




DISCUSSION
            A ternary phase diagram is illustrated in two-dimensions for ease of drawing and reading. This triangular diagram consists of three components, namely ethanol, toluene and water. Toluene is soluble in ethanol but insoluble in water. However, as these three components are mixed until certain proportion, all three components would be completely miscible. Mixture of water and toluene usually form a two-phase system because they are only slightly miscible. However, ethanol is completely miscible with both toluene and water. Thus, the addition of sufficient amount of ethanol to the toluene-water system would produce a single liquid phase (area unbound by the curve) in which all the three components are miscible and the mixture is homogenous. This is shown in the triple phase diagram that has been plotted on the triangular diagram.
            The ethanol / toluene / water system in this experiment involves adding water (as a third component) into a miscible mixture of ethanol and toluene. At first, ethanol and toluene are mixed. Then, we separate the one phase solution into two phases by adding water. As an appropriate amount of water is added, it will result in one phase system. This is known as solvent effect. However, when the ethanol, toluene and water are mixed together, only a partial miscibility can be reached.
                 According to phase rule:
                  P + F = C + 2, where
                  P is the number of phases in the system
                  C is the minimum number of chemical components required to constitute all the phases in the system
                  F is the number of degrees of freedom in the system (also referred to as the variance of the system).
                 For ethanol/toluene/water system, we have 3 components and 1 liquid phase. F= 3-1+2= 4. Hence, 4 degrees of freedom are required, namely temperature, pressure, and the concentrations of two of the three components. Concentration of the third component can be obtained by further calculation. The experiment is carried out at a constant temperature and pressure. The laboratory temperature is 27°C.
                The curve of the plotted graph is termed as binodal curve. Region A bounded by this curve, represent the two-phase region. Mixture with composition contained within region A is cloudy in appearance due to the phase separation. This is due to the fact that the amount of ethanol is not sufficient for homogenous mixture to be produced. Region B of the graph that is not bounded by the binodal curve represents the one-phase region. Mixture with composition that falls into this region is clear, meaning they are homogenous. In other words, the amount of ethanol is sufficient to produce a single liquid phase. 
                Based on the results obtained, when there is a higher percentage of ethanol compared to the percentage of toluene in the mixture, the volume of water needed to titrate the mixture until cloudiness is observed is higher. The appearance of cloudiness indicates that a two-phase system is created. This proves that the ethanol has increased the miscibility of the other two components and more water is needed to break the homogeneity.
            As shown in the triangle, we can see the binomial curve is incomplete and no tie line is obtained as there may be some errors encountered during the experiment. One of the errors is the parallax error. Our eyes must be parallel to the meniscus position when taking reading on burette or pipette. It can make sure the volume taken and recorded is accurate. Next, the degree of cloudiness is unsure. There is wide range of cloudiness that students get confused to stop the titration of water or not. Different degree of cloudiness is achieved because the addition of water is done by different person. This contributes to an excess amount or insufficient amount of water. Besides, the volatility of the chemicals also leads to the error. This is because the mixture of toluene and ethanol may vaporise if it is left longer and unsealed. In addition, the conical flask is not completely dried before the titration. This may result in slight dilution of the mixture.  

PRACTICE:

1.   Does a mixture containing 70% ethanol, 20% water and 10% toluene (volume) appear clear or does it form two phases?

        The solution is appear clear, at these concentrations, showing them appear as one liquid phase.

2.    What will happen if you dilute 1 part of the mixture with 4 parts of (a) water; (b) toluene;(c) ethanol?

        (a)    Water
         The solution appeared in two layers as there are two phases formed.
        (b)    Toluene
         The solution appeared in two layers as there are two phases formed.
  (c)   Ethanol
         The solution appeared in one layer as there is only single phase formed.


CONCLUSION

Phase diagrams are graphical representations of the liquid, vapour, and solid phases that co-exist at various ranges of temperature and pressure within a reservoir. A ternary phase diagram represent the phase behavior of mixtures containing three components in a triangular diagram. This experiment of ternary system involve three different liquids which are ethanol, toluene, and water and is represented using a triangle(ternary phase diagram). In this experiment, as the number of volume of ethanol by percentage increase while the number of volume of toluene by percentage decrease, the volume of water will increase. The two phase system was established once the cloudiness was observed. This shows that water and toluene are only slightly miscible whereas ethanol is completely miscible with both toluene and water.
In the nutshell, the objectives of the experiment are achieved. The solubility limits in a ternary system of water and two other liquids (ethanol and toluene) are determined. The concept of construction of the solubility curve of the system being studied on triangular diagram and concept of miscibility and phase diagram for three-component system are understood. Lastly, Phase Rule are used to relate to the use of triangular coordinates to know the mutual solubility of liquids in a two phase system.

REFERENCE
1.     Martin's Physical Pharmacy and Pharmacautical Science, Sixth Edition, Patrick J. Sinko, Wolters Kluwer, Lippincott Williams & Wilkins.
2.     Syed Shabudeen P.S. , 2010, retrieved from http://www.researchgate.net/publication/265602607_Phase_Rule_CHAPTER-6_PHASE_RULE
3.      Phase Diagrams Of Pure Substances, retrieved from http://www.chemguide.co.uk/physical/phaseeqia/phasediags.html
4.      Physicochemical Principles of Pharmacy, 3rd edition (1998) . A.T. Florence and D.Attwood. Macmillan Press Ltd.